Resolved PHP Curl POST don't works with X-API-Key

[Yannick Croteau]

I'm trying to build a PHP function to get a user loging link in PHP.

The user/pass method works very well

function getLinkUrlWithUser($account, $username, $password, $server){

    $url = "https://" . $server . ":8443/api/v2/cli/admin/call";
    $request = array("params" => array("--get-login-link", "-user", $account));

    # Set curl request
    $ch = curl_init( $url );
    $payload = json_encode($request);
    curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
    curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $payload );
    curl_setopt($ch, CURLOPT_HTTPHEADER, array("Content-Type:application/json", "Accept:application/json")) ;
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true );

    # Send request.
    $result = curl_exec($ch);
    $curl_errno = curl_errno($ch);
    $curl_error = curl_error($ch);
    curl_close($ch);

    # Print response.
    if ($curl_errno > 0) {
        echo "cURL Error ($curl_errno): $curl_error <br/>";
        return "";
    }else{
        $data = json_decode($result);
        if($data->code == 0){
            return $data->stdout;
        }else{
            echo "Curl Error code: $data->code <br/>";
            echo "Error message: $data->stderr <br/>";
            return "";
        };
    };
  
}

but if i'm trying to use the X-API-Key with that one :

function getLinkUrl($account, $secretKey, $server){

    $url = "https://" . $server . ":8443/api/v2/cli/admin/call";
    $request = array("params" => array("--get-login-link", "-user", $account));
    $key = "X-API-Key:$secretKey";

    $ch = curl_init( $url );
    $payload = json_encode($request);
    curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
    curl_setopt($ch, CURLOPT_POSTFIELDS, $payload );
    curl_setopt($ch, CURLOPT_HTTPHEADER, array($key, "Content-Type:application/json", "Accept:application/json")) ;
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true );

    # Send request.
    $result = curl_exec($ch);
    $curl_errno = curl_errno($ch);
    $curl_error = curl_error($ch);
    curl_close($ch);

    # Print response.
    if ($curl_errno > 0) {
        echo "cURL Error ($curl_errno): $curl_error <br/>";
        return "";
    } else {
        $data = json_decode($result);
        if($data->code == 0){
            return $data->stdout;
        }else{
            echo "Curl Error code: $data->code <br/>";
            echo "Error message: $data->stderr <br/>";
            return "";
        }
    }
    
}

I always get back :

code: 1
stderr: You have entered incorrect username or password.

Even if I call a new key, the same result.

P.S. My python variante works very well!

Thank you!
Yannick

 

[Yannick Croteau]

So at the end my code is good. It was a typo in a passed parameter. But the return error gived me a bad clue. If I had a bad json form error or something like that should be more appropriate.

Thank you!